2x(3x-2)+2(x+2)=6x^2+5

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Solution for 2x(3x-2)+2(x+2)=6x^2+5 equation: 



2x(3x-2)+2(x+2)=6x^2+5

We move all terms to the left:

2x(3x-2)+2(x+2)-(6x^2+5)=0

We multiply parentheses

6x^2-4x+2x-(6x^2+5)+4=0

We get rid of parentheses

6x^2-6x^2-4x+2x-5+4=0

We add all the numbers together, and all the variables

-2x-1=0

We move all terms containing x to the left, all other terms to the right

-2x=1

x=1/-2

x=-1/2

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